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Solution :

Initial charge store `= 50 mu C ` <br> Let the dielectric constant of the material induced b and k . Now when the extra charge flow through battery is `100 mu C` . So, net charge stored in capacitor <br> ` = 150 mu C` <br> Now `C_2 = BC_1` <br> ` K eplison_0 A / d_1 = 3 eplison_0 A / d and K = 3` .